ANTI-NUMBERS Antinumbers were created, as were many other things, after lunch, while I was with my good friend Brendon, and my Boyfriend Nick. We were making some math jokes (not nerds), particularly ones regarding bases. To get the theory of atinumbers, one must have some education in the field of bases, and because my web site is read by idiots (ALGEBRA I), I have included a brief lesson: The system which we use for our numbers is the Base 10 system. This means that there are 10 distinct digits (0, 1, . . . 9) that make up all of our numbers. When we count, we start at zero and count upwards to the next highest digit until we reach 9, and then we must add another digit and start back at zero (10). In base 2, also known as binary, there are only two distinct digits, 0 and 1. Counting is the same, except you can only use the two digits. In base 2: 0, 1, 10, 11, 100 is how you count to the Base 10 value of four. There are also bases greater than ten, in which other symbols are used as the numbers beyond 9 ( [. . 8, 9, a, b, 10] could be base 12). In any case, 10 in base x = x in base 10. Hopefully, you now know enough to understand the theory. (Bet you didn't think you'd learn anything on this site) Anyway, we were making jokes having to do with bases, such as: "That was great. I give it a 10. IN BASE THREE!" and "Yeah, we're open twenty-four hours a day. IN BASE FIVE!" and "You're a 10. IN BASE MORON!" Stupid things like that. But it kept us entertained. Me and Nick anyway. Brendon, on the other hand, was prompted to say "If you don't shut up, Im going to beat you 8 times in base negative three!" Me and Nick both had a good laugh over Brendon's idiocy (ALGEBRA I). Obviously, the digit "8" could not exist in any base less than 9, and base negative 3 does not exist. In our efforts to explain this to my good ignorant friend Brendon, we developed the theory of Antinumbers. THE THEORY OF ANTINUMBERS
As you know, in base 10 there are 10 different digits, in base 2 there are 2. In base 0, there are no digits, and in base -1, there is one less than 0 digits. This calls for something that is not a digit, an antidigit. Any negative base system is not a system of numbers, but a system of antinumbers, the reverse of numbers. Do not confuse antinumbers with negative numbers. Negative numbers are real numbers less than zero; they do exist. Antinumbers are neither real nor imaginary numbers, for they cannot be numbers at all. Antinumbers are written as normal numbers, but with omega as a subscript. My computer will not permit me to write this. (I wanted degree signs with frowny faces in them, but Nick would not permit this) All normal functions done with numbers may be done with antinumbers. They can be added, subtracted, squared, and rooted. There are possitive and negative antinumbers, and the number of antidigits is equal to the opposite of the base number. So, just like base 10 cotaining 10 digits, base -10 contains 10 antidigits. (Base anti10 makes your head explode)
anti5 x anti(-6) = anti(-30) However, things get more complicated when one tries to solve a term containing both numbers and antinumbers. There are two hypotheses for this instance:
A) The antinumbers should be converted to numbers by multiplying them by the square root of -1 (i), and the entire term be divided by zero.
1 + anti1 = (1 + i)/0
or
B) The universe explodes.
Should either of these hypotheses be proven, I'll be sure to let you know. |
